Riddle me this!

[NickCrash]

I know I didn't solve the riddle, but let me present one of my own (well not exactly my own, I found it somewhere).

Here you go guys, have a pie. With 3 strikes/slashes you should divide it into 8 equal pieces.

[laggless01]

You cut it in half, stack the pieces, cut it in half (now you have 4), stack the pieces, then cut it in half again (now you have 8).
There's also probably a way to get 8 pieces without stacking, but they won't be equal.

[NickCrash]

No need to stack

a solution is this:

try a bit

are you so curious not to try yourself?

Alright I'll tell you

lol nope

still nope

cut it horizontally

cut as if you were to cut 4 pieces.

the pieces below are just like the ones above

the pieces of the pie don't leave their place

Edited February 18, 2015 by nickcrash

[Dhanush D Bhatt]

No need to stack

a solution is this:

try a bit

are you so curious not to try yourself?

Alright I'll tell you

lol nope

still nope

cut it horizontally

cut as if you were to cut 4 pieces.

the pieces below are just like the ones above

the pieces of the pie don't leave their place

Yup my answer is the same

I ran out of riddles for now. If you guys have any feel free to post

[NickCrash]

Alright ladies and gentlemen,

Five couples are meeting at a restaurant for dinner. Before eating, introductions are mandatory, as some people don't know each other, so they exchange a handshake. Naturally the couple doesn't greet each other, as it is certain to know each other (come on, they are already supposed to be married). When all handshakes stop, I ask everyone how many handshakes they made and receive the answers: 0,1,2,3,4,5,6,7 and 8, but I forgot who said what.

How many handshakes did my waifu make?

[laggless01]

No need to stack

a solution is this:

try a bit

are you so curious not to try yourself?

Alright I'll tell you

lol nope

still nope

cut it horizontally

cut as if you were to cut 4 pieces.

the pieces below are just like the ones above

the pieces of the pie don't leave their place

I found my answer a bit easier and tastier to eat, tbh

[Meruem]

Alright ladies and gentlemen,

Five couples are meeting at a restaurant for dinner. Before eating, introductions are mandatory, as some people don't know each other, so they exchange a handshake. Naturally the couple doesn't greet each other, as it is certain to know each other (come on, they are already supposed to be married). When all handshakes stop, I ask everyone how many handshakes they made and receive the answers: 0,1,2,3,4,5,6,7 and 8, but I forgot who said what.

How many handshakes did my waifu make?

those answers are impossible, someone can't have shaked 8 hands if one of them shaked none (unless they can shake someone's hands more than once)

so ur waifu said she shaked 0 hands cos she a liar :]

or 8 if a slutty liar

idk tho, answer?

[Rosesong]

Funny, but you can't make a handshake, you can only make a milkshake~

Also, I'm going to say 0 because you're asking the couples; there's no indication that you're counting yourself as part of the five couples

[Dhanush D Bhatt]

those answers are impossible, someone can't have shaked 8 hands if one of them shaked none (unless they can shake someone's hands more than once)

so ur waifu said she shaked 0 hands cos she a liar :]

or 8 if a slutty liar

idk tho, answer?

I think what he means is how many started the shake. One will start and the other receives i guess.

As for the riddle, i see no way of approaching it but i will have to guess 0

[NickCrash]

I am in one of those couples (my waifu too).

Alright I'll post the solution

Hints

At first it seems we don't have enough data to solve this, but we do

The person (assuming it's a he) who made 8 handshakes shook everyone's hands except for himself and his wife. So they have greeted him as well (8).

The person who made 0 handshakes is that person's wife. Therefore a couple has 8-0

Next couple: The person making 7 handshakes has greeted everyone, except himself, his wife/husband, and the wife from the previous couple

Therefore everyone has made at least 2 handshakes, except from his wife, who made 1. So, this couple has 7-1 (Germany-Brazil)

Same logic. Next couple 6-2, and the couple following 5-3.

There is one person left, who has made 4 handshakes but belongs to no couple asked yet. Therefore that person can only be my waifu.

[Nova]

I am in one of those couples (my waifu too).

Alright I'll post the solution

Hints

At first it seems we don't have enough data to solve this, but we do

The person (assuming it's a he) who made 8 handshakes shook everyone's hands except for himself and his wife. So they have greeted him as well (8).

The person who made 0 handshakes is that person's wife. Therefore a couple has 8-0

Next couple: The person making 7 handshakes has greeted everyone, except himself, his wife/husband, and the wife from the previous couple

Therefore everyone has made at least 2 handshakes, except from his wife, who made 1. So, this couple has 7-1 (Germany-Brazil)

Same logic. Next couple 6-2, and the couple following 5-3.

There is one person left, who has made 4 handshakes but belongs to no couple asked yet. Therefore that person can only be my waifu.

Damn you, Rickroll.

[Dhanush D Bhatt]

Bumping this thread cause :

1) I got 2 reallly good ones i want to share they may or may not be related to people wearing coloured hats

2) We need moar riddles to solve y/y?

Are you ready for the first riddle?

Here goes :

There is a room of people, each with a hat. Inside the room, there is no means of seeing your own reflection so no one can find out their own hat colour but they can all see the hats of the other people. The following rules are set down

1) There can be no communication between each other

2) The hats are either Blue or Red in colour. The number of Blue or Red hats is unknown and arbitrary.

3) There is at least one Blue hat.

4) A bell will be rung at regular intervals. The bell will be rung the same number of times as the number of people in the room

5) Any one wearing a Blue hat is requested to leave the room at the ring of the bell as soon as possible.

How would the people wearing the Blue hats know they are wearing a blue hat and leave the room? Assume everyone is logical.

If you're going to ask why such a random situation, i'll just stop you and say it's a social experiment or something

Post your answers below and i'll tell you whether they are right or wrong. If you have more riddles, do post them here.

Good luck with this one, you'll really have to think about it

[Wendel]

....Couldn't they just take off their hat to look?

[Dhanush D Bhatt]

For God's sake Wendel, no they can't take off their hats. They aren't allowed to look at their hats in any way.

[Wendel]

You didn't say it anywhere before so lesgo put dem hats off >:C

[Dhanush D Bhatt]

Sigh, ok Wendel you're right.

Now let's change the riddle a bit, THEY CAN'T TAKE OFF THEIR HATS.

[Cepheus]

well... we don't know the number of people inside the room...

so I say:

There are only two people in the room.

that means at least 1 has a blue hat (according to the rules)

if one of the two sees that the other has a red hat, he knows he is wearing a blue hat and has to leave when the bell rings.

HOWEVER... since there is no rule about having any number of red hats it could be possible that both wear blue hats... but both would assume they would wear a red hat!

In that case, when the bell rings, none of them would attempt to leave the room (because they think they have a red hat)...

and then they would know something is strange because the other person doesn't leave the room... and so both people leave the room because the only solution would be that they both wear a blue hat!

Edited January 1, 2016 by Cepheus

[Synchronoise]

Bumping this thread cause :

1) I got 2 reallly good ones i want to share they may or may not be related to people wearing coloured hats

2) We need moar riddles to solve y/y?

Are you ready for the first riddle?

Here goes :

There is a room of people, each with a hat. Inside the room, there is no means of seeing your own reflection so no one can find out their own hat colour but they can all see the hats of the other people. The following rules are set down

1) There can be no communication between each other

2) The hats are either Blue or Red in colour. The number of Blue or Red hats is unknown and arbitrary.

3) There is at least one Blue hat.

4) A bell will be rung at regular intervals. The bell will be rung the same number of times as the number of people in the room

5) Any one wearing a Blue hat is requested to leave the room at the ring of the bell as soon as possible.

How would the people wearing the Blue hats know they are wearing a blue hat and leave the room? Assume everyone is logical.

If you're going to ask why such a random situation, i'll just stop you and say it's a social experiment or something

Post your answers below and i'll tell you whether they are right or wrong. If you have more riddles, do post them here.

Good luck with this one, you'll really have to think about it

Oh God, it's been a long while since I've heard this one. Close to ten years, in fact. Let's see if I can remember the solution

There are multiple scenarios that can happen. Let's assume for presentation's sake that there are five people, and only one blue hat for the first situation

From the perspective of someone with a red hat, they can see that there's exactly one person with a blue hat, so they wouldn't move

From the perspective of someone with a blue hat however, since they don't see anyone else step out, they'll step out by themselves, because of the min. one blue hat

If there's two blue hats, the situation's slightly different.

In the eyes of someone with a blue hat, they can tell that there's another person with a blue hat, so they won't move

After awhile, since the two of them aren't moving, they can independently figure out that there's more than one blue hat in play. Because the guys with the blue hats can only see one other blue hat guy, they can make the assumption that they also have a blue hat, so they'll both walk out

Because the other people see two hats, they're inclined to stay for the next situation.

In this next situation, 3 people are wearing blue hats.

Since nobody moved after the previous situation, you can assume that there are more than two hats in play. Keep in mind that every blue hatted person can see two other hats, so they're inclined to stay. After this, it's just a rinse and repeat of the previous situation, all the way to infinity

[Dhanush D Bhatt]

well... we don't know the number of people inside the room...

so I say:

There are only two people in the room.

that means at least 1 has a blue hat (according to the rules)

if one of the two sees that the other has a red hat, he knows he is wearing a blue hat and has to leave when the bell rings.

HOWEVER... since there is no rule about having any number of red hats it could be possible that both wear blue hats... but both would assume they would wear a red hat!

In that case, when the bell rings, none of them would attempt to leave the room (because they think they have a red hat)...

and then they would know something is strange because the other person doesn't leave the room... and so both people leave the room because the only solution would be that they both wear a blue hat!

Your answer is correct for a two person scenario, try a similar extension for a scenario with several people.

Oh God, it's been a long while since I've heard this one. Close to ten years, in fact. Let's see if I can remember the solution

There are multiple scenarios that can happen. Let's assume for presentation's sake that there are five people, and only one blue hat for the first situation

From the perspective of someone with a red hat, they can see that there's exactly one person with a blue hat, so they wouldn't move

From the perspective of someone with a blue hat however, since they don't see anyone else step out, they'll step out by themselves, because of the min. one blue hat

If there's two blue hats, the situation's slightly different.

In the eyes of someone with a blue hat, they can tell that there's another person with a blue hat, so they won't move

After awhile, since the two of them aren't moving, they can independently figure out that there's more than one blue hat in play. Because the guys with the blue hats can only see one other blue hat guy, they can make the assumption that they also have a blue hat, so they'll both walk out

Because the other people see two hats, they're inclined to stay for the next situation.

In this next situation, 3 people are wearing blue hats.

Since nobody moved after the previous situation, you can assume that there are more than two hats in play. Keep in mind that every blue hatted person can see two other hats, so they're inclined to stay. After this, it's just a rinse and repeat of the previous situation, all the way to infinity

Yes that is the correct solution. If there are two people with blue hats, they would leave at the second bell ring and so on.

On to the second riddle then /o/

A Logician wants to test his students to see how smart they are. He tells them all to sit around in a circle such that each one can see all the others. He puts a coloured hat on all of them. None of them know what colour hat they wear, nor are they allowed to look at their hat in any way. He sets down the following conditions :

1) The number of colours of hats is indefinite, there could be red, blue,black,white , purple or any other colour.

2) A bell will be rung at regular intervals, if you know what colour your hat is, you can get up and tell me what colour your hat is. If you are correct, you pass. Else you fail.

3) You are not allowed to communicate with each other in any way.

4) If i feel like you should have guessed your hat colour already but haven't, you fail.

5) It is impossible to not guess your hat colour throughout the test.

How do the students correctly guess their hat colours?

[Synchronoise]

Your answer is correct for a two person scenario, try a similar extension for a scenario with several people.

Yes that is the correct solution. If there are two people with blue hats, they would leave at the second bell ring and so on.

On to the second riddle then /o/

A Logician wants to test his students to see how smart they are. He tells them all to sit around in a circle such that each one can see all the others. He puts a coloured hat on all of them. None of them know what colour hat they wear, nor are they allowed to look at their hat in any way. He sets down the following conditions :

1) The number of colours of hats is indefinite, there could be red, blue,black,white , purple or any other colour.

2) A bell will be rung at regular intervals, if you know what colour your hat is, you can get up and tell me what colour your hat is. If you are correct, you pass. Else you fail.

3) You are not allowed to communicate with each other in any way.

4) If i feel like you should have guessed your hat colour already but haven't, you fail.

5) It is impossible to not guess your hat colour throughout the test.

How do the students correctly guess their hat colours?

Isn't this similar to the previous one?

[Cepheus]

Your answer is correct for a two person scenario, try a similar extension for a scenario with several people.

Yes that is the correct solution. If there are two people with blue hats, they would leave at the second bell ring and so on.

On to the second riddle then /o/

A Logician wants to test his students to see how smart they are. He tells them all to sit around in a circle such that each one can see all the others. He puts a coloured hat on all of them. None of them know what colour hat they wear, nor are they allowed to look at their hat in any way. He sets down the following conditions :

1) The number of colours of hats is indefinite, there could be red, blue,black,white , purple or any other colour.

2) A bell will be rung at regular intervals, if you know what colour your hat is, you can get up and tell me what colour your hat is. If you are correct, you pass. Else you fail.

3) You are not allowed to communicate with each other in any way.

4) If i feel like you should have guessed your hat colour already but haven't, you fail.

5) It is impossible to not guess your hat colour throughout the test.

How do the students correctly guess their hat colours?

If the professor is unfair... this is the stupidest thing ever... since he puts the hat on you and he can just sit there and define himself a time like 5 minutes... and say "Ok - that's it! I would have already guessed it - you fail!" (he possibly would be able to, since he makes this riddle)

let's say a student answers "red" and indeed his hat is red... BUT there are multiple shades of red... the professor could just ask "which shade of red?" and well... there are A LOT of shades (you know color-coding? #FF0000 and such? - yeah...)

but that is only assuming the professor is a giant...

and we, again, don't know the number of students or if any color is pplied multiple times... we don't know the colors chosen or how many hats there are...

There could be 1 Red hat and the rest green... or 5 different colors each represented two times...

There is just no structure in the hats given out...

But the bell doesn't make sense... why ring it and give them a chance only THEN at this moment to speak up? why not just make them raise their hand?

I would just watch the professor go around and put the hats on the others and see which hat is next, when he arrives at the studend next to me...

or rub my hands on the hat and look at my hands to see if the color is spreading on them

Isn't this similar to the previous one?

not entirely... since there there can be more than 2 different colors...

Edited January 1, 2016 by Cepheus

[Dhanush D Bhatt]

Isn't this similar to the previous one?

It is in a way very similar, if you make one deduction regarding the number of coloured hats.

If the professor is unfair... this is the stupidest thing ever... since he puts the hat on you and he can just sit there and define himself a time like 5 minutes... and say "Ok - that's it! I would have already guessed it - you fail!" (he possibly would be able to, since he makes this riddle)

let's say a student answers "red" and indeed his hat is red... BUT there are multiple shades of red... the professor could just ask "which shade of red?" and well... there are A LOT of shades (you know color-coding? #FF0000 and such? - yeah...)

but that is only assuming the professor is a giant...

and we, again, don't know the number of students or if any color is pplied multiple times... we don't know the colors chosen or how many hats there are...

There could be 1 Red hat and the rest green... or 5 different colors each represented two times...

There is just no structure in the hats given out...

But the bell doesn't make sense... why ring it and give them a chance only THEN at this moment to speak up? why not just make them raise their hand?

I would just watch the professor go around and put the hats on the others and see which hat is next, when he arrives at the studend next to me...

or rub my hands on the hat and look at my hands to see if the color is spreading on them

not entirely... since there there can be more than 2 different colors...

Umm no the professor is completely fair and isn't a douche. The bell rings are very important like the previous riddle. You don't need to know the number of colours or the number of hats of a specific colour like the previous one as well since the solution is a general one. If you want though you can try out a case of say 10 students and how many ever colours and coloured hats. But the solution works for any number of students, any number of colours.

[Synchronoise]

Nah, it's more or less the exact same thing

Here's a hint

If the professor had an infinite number of students, how many colours do you think you'd be able to see?

[Dhanush D Bhatt]

Nah, it's more or less the exact same thing

Here's a hint

If the professor had an infinite number of students, how many colours do you think you'd be able to see?

So you know the answer? If you do you can put it in a spoiler so that only those who want to see it will.

[Synchronoise]

Like I said, solution's similar to the previous one

You have a limited number of colours that you can use. Colours don't go on infinitely, at some point you're coming on to a hard stop. If you have an infinitely larger number of people, you're going to have duplicates. This is where it starts tying into the first solution. From there, you go through the same motions, and you'll be able to deduce your hat colour

But realistically though, both numbers will be on a much smaller scale. Using the entire spectrum of colours would be too confusing, and at the end of the day, the test is on logic, not colour, so the professor's likely to use just a few choice colours that are easy to differentiate. Similarly, there isn't an infinite number of people in the world, much less students, so the number will also go down. But the same thing more or less still applies.